A hard one, help me out!

Mathematics

2 answers:

Elena-2011 [213]3 years ago

6 0

Answer:

(4x-9)(x+8)is the correct answer

Goryan [66]3 years ago

4 0

Answer:

It is the last one: (4x-9)(x+8)

Step-by-step explanation:

You have to split the "b", or split the 23x so that you can perform grouping, and then combine.

You might be interested in

What is the value of x

il63 [147K]

Take 180 and subtract the sum of the two given angle, the answer is 62

6 0

3 years ago

Mohammad divide Rs 82000 into two parts such that the amounts at 5% per annum compound interest in 2 years and 3 years are equal

lara [203]

Answer:

Rs 42000 and Rs 40000

Step-by-step explanation:

Given that Rs 82000 is divided into two parts.

Let the first part be Rs x which is compounded annually at the interest of 5% per annum for 2 years.

The rate of interest = 5%=0.05

The total amount after 2 years $= x(1+0.05)^{2}\cdots(i)$

The other part is Rs 82000-x which is compounded annually at the interest of 5% per annum for 3 years.

The total amount after 3 years $= (82000-x)(1+0.05)^{3}\cdots(ii)$

As both the amounts are equal, so from equation (i) and (ii)

$x(1+0.05)^{2}=(82000-x)(1+0.05)^{3} \\\\x(1.05)^{2}=82000(1.05)^{3} -x(1.05)^{3} \\\\x(1.05^2+1.05^3)=82000\times 1.05^3 \\\\x(2.260125)=94925.25 \\\\x=94925.25/2.260125 \\\\$

x= 42000

And the other part = 82000-42000 = Rs 40000

Hence, he divides the money as

Rs 42000 at 5% per annum compound interest in 2 years and

Rs 40000 at 5% per annum compound interest in 3 years.

4 0

3 years ago

What is the volume of the rectangular prism?

Rufina [12.5K]

Answer:

$\large\boxed{Q1.\ 80\ cm^3}\\\boxed{Q2.\ 45\ in^3}\\\boxed{Q3.\ 48\ m^3}\\\boxed{Q4.\ A,\ D}\\\boxed{Q5.\ 96\ in^3}$

Step-by-step explanation:

$\text{The formula of a volume of a rectangular prism:}\\\\V=lwh\\\\l-length\\w-width\\h-height$

$\bold{Q1}\\\\l=10\ cm,\ w=4\ cm,\ h=2\ cm\\\\V=(10)(4)(2)=80\ cm^3\\\\\bold{Q2.}\\\\l=5\ in,\ w=3\ in,\ h=3\ in\\\\V=(5)(3)(3)=45\ in^3\\\\\bold{Q3.}\\\\l=4\ m,\ w=2\ m,\ h=6\ m\\\\V=(4)(2)(6)=48\ m^3\\\\\bold{Q4.}\\\\V=120\ ft^3\\\\\bold{A:(5)(4)(6)=120}\\B:\ (7)(7)(6)=294\\C:\ (3)(6)(4)=72\\\bold{D:\ (10)(3)(4)=120}\\\\\bold{Q5.}\\\\l=8\ in,\ w=4\ in,\ h=3\ in\\\\V=(8)(4)(3)=96\ in^3$