There are 62 dimes and 44 nickels.
N + D = 106 (There are 106 coins in all.)
1 nickel = 5 cents.
1 dime = 10 cents.
5*N + 10*D = 840 ($8.40 = 840 cents)
N + D = 106 -------(1)
N = (106 - D)
5*N + 10*D = 840 ---------(2)
5*(106-D) + 10*D = 840
530 - 5*D + 10*D = 840
5*D = 840 - 530
5*D = 310
D = 310/5 = 62
Eq(1) N + D = 106
N + 62 = 106
N = 106 - 62
N = 44
<span>the product of one term of a multiplicand and one term of its multiplier.</span>
6/12 or 1/2 I hope this was the right answer and helped you
Step-by-step explanation:
Individual differences is the answer hshahaha
Answer:
3,-1
Step-by-step explanation:
you go over to the left 3 and than you go down 4.