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Romashka-Z-Leto [24]
3 years ago
5

Please help!!! If you can

Mathematics
2 answers:
shepuryov [24]3 years ago
5 0

y = 12000 {(1.04)}^{30}

Merton's population = 38920.77012

//

18000 + 30(500) = 33000

Hapville's population = 33000

//

38920.77012 - 33000 = 5920.77012

5920.77012 ---> 6000

The answer is B.

kirill [66]3 years ago
4 0

Answer:

Im guessing its B. Im sorry of this didnt help.

Step-by-step explanation:

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Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

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Start by calculating the equations of f(x) and g(x)

<u>Graph f(x)</u>

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So, the equation is:

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So, we have:

\mathbf{h(x) = f(g(x))}

Where:

\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2} and \mathbf{g(x) = -\frac 12x}

\mathbf{h(x) = f(g(x))} becomes

\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}

Open brackets

\mathbf{h(x) = -\frac{3}{4}x}

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So:

\mathbf{h'(1) = -\frac{3}{4}}

\mathbf{h'(2) = -\frac{3}{4}}

For x = 3, we have:

\mathbf{h(x) = f(g(x))}

Where:

\mathbf{f(x) = -\frac{3}{2}x\  x \ge 2} and \mathbf{g(x) = -\frac 12x}

\mathbf{h(x) = f(g(x))} becomes

\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}

\mathbf{h(x) = \frac{3}{4}x}

Differentiate

\mathbf{h'(x) = \frac{3}{4}}

Substitute 3 for x

\mathbf{h'(3) = \frac{3}{4}}

Hence, the values of the derivatives are:

\mathbf{h'(1) = -\frac{3}{4}}, \mathbf{h'(2) = -\frac{3}{4}} and \mathbf{h'(3) = \frac{3}{4}}

Read more about graphed functions at:

brainly.com/question/11804653

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Answer:

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