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3 years ago

11

Help me pls i need help

2 answers:

podryga [215]3 years ago

8 0

<h2><em>Hii</em><em>.</em><em>.</em></h2>

<h2><em> </em><em>-45 - 13 = 10x</em></h2><h2 /><h2><em> </em><em>-58 = 10x</em></h2><h2 /><h2><em> </em><em>-58 / 10 = x</em><em> </em><em> </em><em> </em></h2>

<h2><em> </em><em>x = - 5.</em><em>8</em></h2>

<h2><em>Have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>time</em><em>!</em><em>!</em></h2>

<h2 />

Lunna [17]3 years ago

5 0

Answer:

Exact Form: -29/5

Decimal Form:-5.8

Mixed Number Form:-5 4/5

Step-by-step explanation:

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The annual income of Sam is Rs 43,360. What is his monthly income if he earns an equal amount every month?

tankabanditka [31]

His monthly income if he earns an equal amount every month is Rs 3,613.33

<h3>How to determine the monthly income?</h3>

The annual income is given as:

Annual income = Rs 43,360

The monthly income is calculated as

Monthly income = Annual income/Number of months

There are 12 months in a year

So, we have:

Monthly income = Rs 43,360/12

Evaluate the quotient

Monthly income = Rs 3,613.33

Hence, his monthly income if he earns an equal amount every month is Rs 3,613.33

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2 years ago

What is the probability of tossing a coin three times and getting heads<br> each time? *

Serggg [28]

Answer:

probability of tossing a coin 3 times and getting heads each time is 1/8

Step-by-step explanation:

A coin has 2 sides (heads and tails) therefore you have a 50% chance of getting either heads or tails for each toss. Therefore, the probability of getting heads for 1 toss is 1/2. Now, tossing it 3 times and getting heads each time essentially means you would have to do (1/2)×(1/2)×(1/2) which would give you 1/8 as the probability of tossing a coin 3 times and getting heads each time.

5 0

3 years ago

The Alvin Secretarial Service procures temporary office personnel for major corporations. They have found that 60% of their invo

Hoochie [10]

Answer:

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

Step-by-step explanation:

For each invoice, there are only two possible outcomes. Either they are paid within 10 working days, or they are not. The probability of an invoice being paid within 10 working days is independent of other invoices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

60% of their invoices are paid within ten working days.

This means that $p = 0.6$

A random sample of 18 invoices is checked.

This means that $n = 18$

What is the probability that at least 6 of the invoices will be paid within ten working days?

Either less than 6 are paid within 10 working days, or at least 6 are paid. The sum of the probabilities of these events is 1. So

$P(X < 6) + P(X \geq 6) = 1$

We want $P(X \geq 6)$ . So

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.6)^{0}.(0.4)^{18} \approx 0$

$P(X = 1) = C_{18,1}.(0.6)^{1}.(0.4)^{17} \approx 0$

$P(X = 2) = C_{18,2}.(0.6)^{2}.(0.4)^{16} \approx 0$

$P(X = 3) = C_{18,3}.(0.6)^{3}.(0.4)^{15} = 0.0002$

$P(X = 4) = C_{18,4}.(0.6)^{4}.(0.4)^{14} = 0.0011$

$P(X = 5) = C_{18,5}.(0.6)^{5}.(0.4)^{13} = 0.0045$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0 + 0 + 0 + 0.0002 + 0.0011 + 0.0045 = 0.0058$

Finally

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.0058 = 0.9942$

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

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3 years ago

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aliina [53]

Answer:

sin D

Step-by-step explanation:

i think

or cos D

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3 years ago

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Svetllana [295]

Step-by-step explanation:

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3 years ago