Your answer will be 2.181818
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
Step-by-step explanation:
x^2 and -x^2 would cancel
and then it would be -7 = 1
it would be no solution
but I don't know, someone can prove me wrong I may have a lapse in my algebra at the moment
Around 5.4572271...% decrease
(i’m not sure what to round it to)
subtract 192,300 from 203,400 to find the amount of change
(= 11,100)
then divide that amount from the original price (203,400)
then multiply that number by 100 to get a percent
finally round to a reasonable percent
