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3 years ago

What are the differences and relationships between a dependent variable and an independent variable?

Chemistry

2 answers:

Afina-wow [57]3 years ago

6 0

Explanation:

A dependent variable depends on the independent variable. The independent variable is what you usually control in a experiment.

Tanzania [10]3 years ago

3 0

I think of independent and dependent as in real life. Say there’s a person that’s independent meaning they don’t rely on someone. On the other hand if there’s a person that’s dependent they have to rely on someone. I hope this helped

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What current (in a) is required to plate out 1. 22 g of nickel from a solution of ni2 in 0. 50 hour?

Mashcka [7]

The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

<h3>What is current?</h3>

The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

$\rm Ni^{2+}+2e^-\;\rightleftharpoons Ni$

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

$\rm 58.7\;g=2\;\times\;96487\;C\\58.7\;g=192974\;C$

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

$\rm 58.7\;grams\;Ni=192974\;C\\\\1.22\;grams\;Ni=\dfrac{192974}{58.7}\;\times\;1.22\;C\\\\1.22\;grams\;Ni=4010.7\;C$

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

$\rm Charge=Current\;\times\;Time\\4010.7\;C=Current\;\times\;1800\;sec\\Current=2.23\;A$

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

Learn more about current, here:

brainly.com/question/23063355

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7 0

2 years ago

How many grams of O2 are needed to react with 8.15 g of C2H2?

xxTIMURxx [149]

Answer:

25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

C₂H₂: 2 moles
O₂: 5 moles
CO₂: 4 moles
H₂O: 2 moles

The molar mass of each compound is:

C₂H₂: 26 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

C₂H₂: 2 moles* 26 g/mole= 52 g
O₂: 5 moles* 32 g/mole= 160 g
CO₂: 4 moles* 44 g/mole= 176 g
H₂O: 2 moles* 18 g/mole= 36 g

Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

$mass of O_{2} =\frac{8.15 grams of C_{2} H_{2}*160 grams of O_{2} }{52 grams of C_{2} H_{2}}$

mass of O₂= 25.08 grams

<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>

8 0

3 years ago

Choose the correct statements about solutions.

Svetradugi [14.3K]

I think the answer is C

8 0

3 years ago

PLEASE PLEASE HELP<br> Calculate the mass of 3.4 moles of nitric acid (HNO3)

Elza [17]

Molar mass of nitric acid (HNO3) =atomic mass of hydrogen + atomic mass of nitrogen +3x atomic mass of oxygen . The molar mass of nitric acid (HNO3) is 63.0144 gram per mole, but you have 3.4 moles. Therefore; the answer is 63.0144 g/mole x 3.4 moles = 214.24896 grams.

6 0

3 years ago

Atomic size generally wha?

kipiarov [429]

Decreases as you move left to right

3 0

3 years ago