Answer:
I attached the answer as an image. I also drew in the two most acidic hydrogens.
Explanation:
This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).
Answer:
A. weak acid and its conjugate base
Explanation:
A buffer solution can be made with a weak acid and conjugate base or a weak base and conjugate acid.
This may help you:
https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Acids_and_Bases/Buffers/Introduction_to_Buffers
The balanced chemical reaction is written as:
<span>2K + F2 ---> 2 KF
We are given the amount of potassium metal to be used in the reaction. This will be the starting point for the calculation. We do as follows:
23.5 g K ( 1 mol / 39.1 g ) ( 1 mol F2/2 mol K ) ( 22.4 L / 1 mol ) = 13.46 L F2
</span>
An atom of Oxygen. Contains:
Protons = 8
Electrons = 8
Neutrons = Mass number - Number of protons = 18 - 8 = 10
Neutrons = 10.
Answer:
An atom is composed of them
Explanation:
