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Elden [556K]
4 years ago
12

You need to prepare a sample containing 0.20 g of CuSo from a solution that is 10% Cuso, by mass. What mass of

Chemistry
1 answer:
Andru [333]4 years ago
4 0

Answer:

Mass of solution = 2 g

Explanation:

Given data:

Mass of CuSO₄ = 0.20 g

Percent by mass = 10%

Mass of solution needed = ?

Solution:

Formula:

Percent by mass = mass of solute / mass of solution × 100

Now we will put the values.

10 = 0.20 g/ mass of solution × 100

10/ 100 = 0.20 g/ mass of solution

0.1 = 0.20 g/ mass of solution

Mass of solution =  0.20 g/ 0.1

Mass of solution = 2 g

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A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?
mash [69]

Answer:

<h2>Density = 1.67 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 50 g

volume = 30 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{50}{30}  \\  =  \frac{5}{3}  \\  = 1.66666...

Wr have the final answer as

<h3>Density = 1.67 g/mL</h3>

Hope this helps you

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Svetradugi [14.3K]
Yes they do if that was your question
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Which of the following will increase the number of collisions without changing the energy of reactant molecules?
natulia [17]

Answer:increasing the concentration of reactants

Explanation:

Collision is the phenomenon in which the reactant molecules come to nearest closness,as a result the reactants are converted into products.

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6 0
3 years ago
How to calculate precision chemistry.
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Answer:

Subtract The <u>mean</u> from each Numbers Given

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3 years ago
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
3 years ago
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