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iren [92.7K]
3 years ago
9

2 Points

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

36

Step-by-step explanation:

someone told me. this will make it easier for u

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How are real numbers used to describe real world situations
kenny6666 [7]
Real number are used to explain real situations by allowing you to understand that they will always have an outcome that is disable by another real number
4 0
3 years ago
Can somebody help me with these 2 questions and show work ?? :)
777dan777 [17]

5. A. (4, -2)

6. C. (x, y) — (x, -y + 5)

Step-by-step explanation:

5. For the formula y = x, the x and y coordinates get swapped.

M = (-2, 4) — M’ = (4, -2)

6. If the coordinates get reflected across the x-axis, the y coordinates become negative.

(x, y) — (x, -y)

Now that the coordinates are reflected, you go 5 units up (+ 5) to get to the reflection of the coordinates if it was 5 units down before it reflected across the x-axis (- 5).

Ex. 1, 6 gets reflected across the x-axis and moved 5 units up. It’s reflection would be equivalent to (1, -1) because it moved 5 units down (1, 1) then reflected across the x-axis (1, -1).

(x, y - 5) reflected across the x-axis is equivalent to (x, -y + 5)

8 0
3 years ago
Suppose x represents an objects weight on Earth. Write two expressions: one that you can use to find the objects weight on Mars
tatyana61 [14]
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
4 0
3 years ago
sand falls from an overhead bin and accumulates in a conical pile with a radius that is always four times its height. suppose th
blagie [28]

Answer:

\frac{dv}{dt} =7239.168 cm/sec

Step-by-step explanation:

From the question we are told that:

Rate \frac{dh}{dt}=1cm

Height h=12cm

Radius r=4h

Generally the equation for Volume of Cone is mathematically given by

V=\frac{1}{3}\pi r^2h

V=\frac{1}{3}\pi (4h)^2h

Differentiating

\frac{dv}{dt} =\frac{16}{3}\pi3h^2\frac{dh}{dt}

\frac{dv}{dt} =\frac{16}{3}*3.142*3*12^2*1

\frac{dv}{dt} =7239.168 cm/sec

7 0
2 years ago
A line through which two points would be parallel to a line with a slope of 3/4?
Mumz [18]

Answer:

F. (0, 5) and (-4, 2)

Step-by-step explanation:

We need to calculate the slope of each of the given sets of points until we find the set associated with a slope of 3/4:

F. (0,5) and (-4,2) As we go from (-4, 2) to (0,5), x increases by 4 and y increases by 3, so the slope is m = rise / run = 3/4. This is the line with slope 3/4.

5 0
3 years ago
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