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cricket20 [7]
2 years ago
14

Distance 22

Mathematics
1 answer:
natta225 [31]2 years ago
4 0

Answer:

Use the formula r = d/t. Your rate is 24 miles divided by 2 hours, so: r = 24 miles ÷ 2 hours = 12 miles per hour. Now let's say you rode your bike at a rate of 10 miles per hour for 4 hours.

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A simple random sample of 20 days in which Parsnip ate seeds was selected, and the mean amount of time it took him to eat the se
bearhunter [10]

Answer:

(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63

(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83

And the confidence interval for this case -1.63 \leq \mu_1 -\mu_2 \leq 2.83

Step-by-step explanation:

We know the following info from the problem

\bar X_1 = 14.5 sample mean for the group 1

s_1 = 3.98 the standard deviation for the group 1

n_1= 20 the sample size for group 1

\bar X_2 = 13.9 sample mean for the group 2

s_1 = 4.03 the standard deviation for the group 2

n_2= 17 the sample size for group 2

We have all the conditions satisifed since we have random samples.

We want to construct a confidence interval for the true difference of means and the correct formula for this case is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

The degrees of freedom are given :

df = n_1 +n_2- 2 = 20+17-2=35

The confidence level is 0.9 or 90% and the significance level is \alpha=1-0.9=0.1 and \alpha/2 = 0.05 and the critical value for this case is:

t_{\alpha/2} = 1.69

And replacing the info given we got:

(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63

(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83

And the confidence interval for this case -1.63 \leq \mu_1 -\mu_2 \leq 2.83

5 0
3 years ago
The basic ratio for 24:56
kogti [31]
24:56 = 3:7
You can simplify it by dividing with 2 
5 0
3 years ago
Read 2 more answers
how much is 81% of 403? find the missing element in the following base-rate-percentage problem. round the answer to the nearest
mihalych1998 [28]
4.03 x over 403 81 over 100 and cross multiply
5 0
3 years ago
Can someone help with 6
olga nikolaevna [1]

A. there are 20 boys and 30 girls.

B.

68.7 out of 100 Boys

Girls im not sure, maybe someone else can answer that sorry




Hope I'm right and this helps sorry i didn't get girls.

8 0
3 years ago
I just need to know if these are parallel please,,,
Nataly_w [17]
These are parallel !
4 0
3 years ago
Read 2 more answers
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