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3 years ago

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lisov135 [29]3 years ago

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D.By an open window

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At the Butler Ski Resort, it snowed 1/2 of a foot yesterday and 1/5 of a foot today. How much more did it snow yesterday than to

barxatty [35]

It snowed $\frac{3}{10}$ foot more yesterday than today

<em><u>Solution:</u></em>

Given that, At the Butler Ski Resort, it snowed 1/2 of a foot yesterday and 1/5 of a foot today

From given information,

$\text{Snowed yesterday } = \frac{1}{2} \text{ foot }\\\\\text{Snowed today } = \frac{1}{5} \text{ foot }$

<em><u>To find: how much more did it snow yesterday than today</u></em>

So we have to find the difference between snowed yesterday and today

$\text{Difference} = \text{Snowed yesterday } - \text{ snowed today }\\\\\text{Difference} = \frac{1}{2} - \frac{1}{5}\\\\\text{Difference} = \frac{1 \times 5}{2 \times 5}-\frac{1 \times 2}{5 \times 2}\\\\\text{Difference} = \frac{5}{10}-\frac{2}{10}\\\\\text{Difference} =\frac{3}{10}$

Hence it snowed $\frac{3}{10}$ foot more yesterday than today

3 0

3 years ago

Escreva uma equação do 2 grau que tenha: a) - 5 e 3 como raízes. b) x, +x, = 17 x, x = 70, sabendo que x, e x, são as raízes. =

umka21 [38]

Can u translate in English for me

7 0

3 years ago

If the rectangle below has an area of 40sq. units, what is the area of the triangle?

pshichka [43]

Answer:

The answer is A.

Step-by-step explanation:

Given that the formula of area of triangle is, A = (1/2)×b×h. Then substitute the following values into the formula :

b = 10 units

h = 4 units

A = (1/2)×10×40

= (1/2)×40

= 20 units²

5 0

3 years ago

I dont understand what to do and what the answer is

hodyreva [135]

Answer:

-1

Step-by-step explanation:

slope=(y2-y1)/(x2-x1)=(2-4)/(0+2)=-2/2=-1

3 0

2 years ago

Read 2 more answers

What is the difference?

Whitepunk [10]

Answer:

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

Step-by-step explanation:

Given

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

Required

Calculate the difference

We start by factorizing the denominator of both fractions

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

$\frac{x}{x^2+3x - 5x -15} - \frac{4}{x^2+7x - 5x-35}$

$\frac{x}{x(x+3) - 5(x +3)} - \frac{4}{x(x+7) - 5(x+7)}$

$\frac{x}{(x-5) (x +3)} - \frac{4}{(x-5)(x+7)}$

Take LCM

$\frac{x(x+7) - 4(x +3)}{(x-5) (x +3)(x+7)}$

Open Brackets

$\frac{x^2+7x - 4x -12}{(x-5) (x +3)(x+7)}$

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

This can't be simplified any further;

4 0

3 years ago