The answer would be option 1, mass divided by volume
Answer:
0.81
Step-by-step explanation:
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9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Where 1/4 represents Bob and 1/6 represents Ted...
1/4x + 1/6x = 1
Multiply the two so there is no fraction by the GCF of 12.
3x + 2x = 12
Add 3x and 2x.
5x = 12
Divide by 5.
x = 12
Plug this value in.
With that, the answer is 2 hours and 24 minutes with x = 12 meaning 144 minutes.