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3 years ago

I need some help with this and with the other 6 question! Help this girl in need

Mathematics

2 answers:

Vinil7 [7]3 years ago

6 0

Answer:

y = 2x-6

Step-by-step explanation:

Slope intercept form:

y = mx+b

m = slope

In this case the slope is 2/1 or 2.

b = The point where the line crosses the y-axis

In this case -6 is the exact point the line crosses the y-axis

So if you put it all together you get the answer of:

y = 2x-6

I hope this helped!

P.S. I am so sorry I couldn't respond earlier :(

Sincerely,

Rekifromsk8theinfinity

kirill [66]3 years ago

4 0

Answer:

i think it is y=15x-6

Step-by-step explanation:

if it is correct plz plz mark as brainliest

thank you

19NBoli

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4 years ago

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ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

$f(x)=x^4-x^3-7x^2+13x-6$

According to rational roots theorem,

$\pm1,\pm2,\pm3,\pm6$ are possible rational zeros of

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We find out that,

$f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6$

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$f(-3)=0$

Also

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$f(2)=16-8-28+26-6$

$f(2)=6-6$

$f(2)=0$

This implies that

$x-2 and x+3$ are factors of

$f(x)=x^4-x^3-7x^2+13x-6$ and hence $(x-2)(x+3)=x^2+x-6$ is also a factor.

We perform the long division as shown in the diagram.

Hence,

$f(x)=(x-2)(x+3)(x-1)^2$ .

ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots

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Also the root $x=1$ has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.

Now we determine the position of the graph on the following intervals,

$x\le -3$

$f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6$

$f(-4)=150\:>0$

$-3\le x \le 1$

$f(0)=-6\:$

$1\le x\le 2$

$f(1.5)=-0.56\:$

$x \ge 2$

$f(3)=24\:>0$

We can now use these information to sketch the function as shown in diagram

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