Step-by-step explanation:
a) 3x + 5y = 8
4x - 3y = 1
• using the elimination method:
3x + 5y = 8 (×4)
4x -3y = 1 (×3)
12x + 20y = 32
12x -9y = 3
subract 12x from both equation:
20y - - 9y= 32 -3
20y +9y = 29
29y= 29
y= 29/29
y= 1
- substituting y= 1 in :
4x - 3y= 1
4x - 3(1) = 1
4x -3 = 1
4x = 1 + 3
x = 4/4
x= 1
b) 6p+ 4q = 20
5p - 2q = 6
• using the elimination method:
6p + 4q = 20
5p - 2q = 6 (×2)
6p + 4q = 20
10p - 4q = 12
add 4q + -4q to eliminate q.
6p+ 10p = 20+12
16p = 32
p = 32/ 16
p = 2
- subtituting p = 2 in :
5p - 2q = 6
5(2) -2q =6
10 -2q = 6
-2q = 6 - 10
q = -4 / -2
q = 2
hope this helps you,
-s.
Answer:
64
Step-by-step explanation:
Answer:
Which equation do I refer to?
Step-by-step explanation:
I'm assuming that you meant:
1
f(x) = -------- and that you want to find the value of x at which f(x) = h(x).
x+1
Of course you could create a table for each f(x) and h(x), but setting f(x)=h(x) and solving for x algebraically would be faster and more efficient:
1
f(x) = -------- = 2x + 3 = h(x). Then 1 = (x+1)(2x+3) = 2x^2 + 3x + 2x + 3
x+1
or 1 = 2x^2 + 5x + 3, or 2x^2 + 5x + 2 = 0.
This is a quadratic equation with a=2, b=5 and c=2. The discriminant is b^2-4ac, or 5^2-4(2)(2), OR 25-16= 9.
Thus, the roots are
-5 plus or minus sqrt(9)
x = ------------------------------------
2(2)
-5 plus or minus 3
= ----------------------------------
4
= {-1/2, -2}
Thus, f(x) = h(x) at both x=-1/2 and x= -2.
You dont have a image attached