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2 years ago

Round 0.485 correct to 1 significant figure

Mathematics

1 answer:

yanalaym [24]2 years ago

6 0

Answer:

0.5

Step-by-step explanation:

the first significant figure is the non zero

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What is 22,159 rounded to the nearest hundred?

andre [41]

22,200
**************************************************************************

6 0

3 years ago

Please help (photo attached below) ALGEBRA 1

frutty [35]

Answer:

x =2

2 in, 6 in, 1 in

Step-by-step explanation:

3 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

Factor completely, then place the answer in the proper location on the grid.<br><br> a^6 - 25b^2

Solnce55 [7]

This is the difference of 2 squares

square root of a^6 = a^3
and square root of 25 b^2 = 5b so we get

(a^3 + 5b)(a^3 - 5b)

Thats the answer

5 0

3 years ago

Megan purchased a new gadget for her technology hobby. She plans to sell it sometime in the future, however, its value depreciat

ElenaW [278]

Answer:

The second term defines the value that will be depreciated by the rate of 22 units for m months.

Step-by-step explanation:

Given is :

The value of the gadget after 'm' months = 2020 - 22m

This expression tells us that, each month Meghan's gadget's price falls by 22 units from the original value.

The original value of the gadget is 2020 units.

Therefore, the constant term (2020 )of the expression represents the original value of the gadget,

And the second term defines the value that will be depreciated by the rate of 22 units for m months. And m defines the number of months Meghan will keep the gadget.

5 0

3 years ago