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2 years ago

Find the mean, median, mode, and range for the following numbers.

Mathematics

1 answer:

belka [17]2 years ago

3 0

Answer:

mode 22,28 and 29 range=09 mean 27 hop it helps

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Mr. Bulky’s Candy Emporium sells all candy items for $0.60 per ounce. Penny and Ruth each bought several different types of cand

exis [7]

Answer: what’s the rest of the question? You didn’t provide enough data…✨

Step-by-step explanation:

4 0

2 years ago

What does X equal? geometry

Otrada [13]

Answer:

x= 77

Step-by-step explanation:

The angle at 122 degrees is a linear pair with the isosceles triangle, meaning it makes 180 degrees.

180-122= 58 degrees

Since it is an isosceles triangle, the two angles at the bottom are both 58 degrees.

Let's use this info to find the degree at the top.

58+58= 116

There are 180 degrees in a triangle, so subtract 116 degrees we have so far to find the last angle.

180-116= 64 degrees

And since the angle at the top makes 90 degrees, we can subtract 64 degrees to find the smaller angle to the right of the 64 degree angle.

90-64= 26 degrees

And since a triangle has a total of 180 degrees, subtract the 26 degrees from 180.

180-26= 154 degrees.

And since it is an isosceles triangle, divide the remaining 154 degrees by 2 because they are both equal.

154/2= 77 degrees.

Your answer is 77 degrees.

3 0

2 years ago

I need help finding the mean median mode and range of 62, 35, 46, 35, and 89

adell [148]

Mean-53.4
Median-46
Mode-35
Range-54
Good luck!

6 0

2 years ago

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The figure is transformed as shown in the diagram. Describe the transformation.

Doss [256]

D is the correct answer

5 0

2 years ago

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Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive

Nimfa-mama [501]

The equation to derive the distance d is $\sqrt{(x2-x1)^2+(y2-y1)^2}$ . The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

$d = \sqrt{(x2-x1)^2+(y2-y1)^2}$

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= $\sqrt{(x2-x1)^2+(y1-y1)^2}$

= $\sqrt{(x2-x1)^2+0}$

= $(x2-x1)$

Length of the opposite side: (x2, y1) to (x2, y2)

= $\sqrt{(x2-x2)^2+(y2-y1)^2}$

= $\sqrt{0+(y2-y1)^2}$

= $(y2-y1)$

Therefore, the derived distances for the given triangle are:

$d=\sqrt{(x2-x1)^2+(y2-y1)^2}$ , (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

4 0

1 year ago