With the help of the ratio method, we conclude that 72 grams of sugar should be added.
<h3>
What is Ratio Method?</h3>
- In the ratio method, we compare two quantities by equating their two ratios; this equation is also referred to as a proportion.
- The cross-multiplication method will be used to solve it.
So, 'n=5' will be the number of rings.
- 'w = 18 grams' will be the weight of each ring.
- Total weight: w₀ = n × w = 5 × 18 = 90 grams
Let 's' be silver. Then,
- New weight: wₙ = s + 90
- Old % of gold: p₀ = 90% = 0.9
- New % of gold: pₙ = 50% = 0.5
Now, use the ratio method as follows:
![\frac{w_o}{w_n}=\frac{p_n}{p_o}](https://tex.z-dn.net/?f=%5Cfrac%7Bw_o%7D%7Bw_n%7D%3D%5Cfrac%7Bp_n%7D%7Bp_o%7D)
![\frac{90}{s+90}=\frac{0.5}{0.9}](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7Bs%2B90%7D%3D%5Cfrac%7B0.5%7D%7B0.9%7D)
- 90 × 0.9 = 0.5 × (s + 90)
- 81 = 0.5s + 0.5 × 90
- 81 = 0.5s + 45
- 81 - 45 = 0.5s
- 36 = 0.5s
- 36/0.5 = s
- 72 = s
- So, s = 72
Therefore, with the help of the ratio method, we conclude that 72 grams of sugar should be added.
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The correct question is given below:
A jeweler has five rings, each weighing 18 grams, made of alloys of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 50%. How much silver should he add?
M and O are congruent
N, M and O are similar
<h3>Your answer is: M and N are similar but not congruent</h3>
M and N are similar because the sides of M are proportional to sides of N:
![\dfrac{2}{4}=\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B4%7D%3D%5Cdfrac%7B1%7D%7B2%7D)
Two figures are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.
1 * 10^6
comma is moved back 6 times
Answer:
Use fraction circles to add: 1% + 1% | Use fraction circles to model 1% and 1%. Whole and 1 Whole and 1 Whole and 1 eighth equals 3 wholes and 1 eighth. - Add the fractions and add the whole numbers separately. or: 0 Write each mixed number as an improper fraction, then add.
Step-by-step explanation: