Answer:2x+8=2
2x=2-8
2x= -6 (devide both sides by 2 to get x)
2x/2 and -6/2
×=3
Step-by-step explanation:
There needs to be values to answer the question.
I believe it should be (c)?
Answer:
30. 2x²-x-1=0
or, 2x²-2x+x-1=0
or, 2x(x-1)+1(x-1)=0
or, (x-1)(2x+1)=0
so, x-1 = 0 or, x = 1
and 2x+1 = 0 or, 2x = -1 or, x = -1/2
so, x = 1 and 1/2
31. 3x²-14x=5
or, 3x²-14x-5=0
or, 3x²-15x+x-5=0
or, 3x(x-5)+1(x-5)=0
or, (x-5)(3x+1)=0
so, x-5=0 or, x=5
and 3x+1=0 or, 3x=-1 or, x=-1/3
so, x = 5 and -1/3
Answered by GAUTHMATH
You can use the process elimination to solve. In other words, subtract or add the equations like normal.
5x + 2y = -15
+ 2x - 2y = -6
Because there is a 2y and -2y, we can add both equations to eliminate the y so that we can figure out what x is:
5x + 2x = 7x
2y + (-2y) = 0
-15 + (-6) = -21
We now have 7x = -21
Divide all by 7 to get x = -3
Plug in -3 to any of the two equations. I will use the second equation:
2(-3) - 2y = -6
-6 - 2y = -6
-2y = 0
y = 0
This means that the solution to the system of equations is (-3, 0) in the form of (x, y).
