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erik [133]
3 years ago
10

HELPPPPPPPPPPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
maria [59]3 years ago
3 0
36. R1 = 0.8 and r2= 0.92
R1+ r2= 0.8+ 0.92= 1.72

37. 2000= 3276.8• 0.92 ^(t-5)
2000/3276= 0.92^(t-5)
0.61= 0.92^(t-5)
Log 0.92(0.61)= t-5
5.92= t-5
T= 10.92

38. Remainder is 108
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Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passe
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Step-by-step explanation:

The probability of a component passing the test is, P (S) = 0.79.

The probability that a component fails the test is, P (F) = 1 - 0.79 = 0.21.

Three components are sampled.

Compute the probability of the test result as SFS as follows:

P (SFS) = P (S) × P (F) × P (S)

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Compute the probability of the test result as SSF as follows:

P (SSF) = P (S) × P (S) × P (F)

            =0.79\times0.79\times0.21\\=0.131061\\\approx0.1311

Thus, the probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

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3 years ago
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