Answer:
As shown in picture:
A(-4, 1)
Z(-2, 3)
P(3, -4)
The length of AZ is calculated by:
L = sqrt((-4 - -2)^2 + (1 - 3)^2) = 2.83
The length of AP is calculated by:
L = sqrt((3 - -4)^2 + (-4 - 1)^2) = 8.60
THe length of ZP is calculated by:
L = sqrt((3 - -2)^2 + (-4 - 3)^2) = 8.60
=>Perimeter of triangle AZP is calculated by:
P = AZ + AP + ZP = 2.83 + 8.60 + 8.60 = 20.3
Hope this helps!
:)
x = 8
Explanation:
AE = 3x - 4
EC = x + 12
SInce diagonals AC and DB intersect at E
it means the lines which meet at the intersection E are equal. A and C meet at E which gives AE and EC
AE = EC
3x - 4 = x + 12
collect like terms:
3x - x = 12 + 4
2x = 16
divide both sides by 2:
2x/2 = 16/2
x = 8
165 divided by 11 equals 15
