Answer:
Distance swam by Sonya in 3 weeks = 19740 m
Step-by-step explanation:
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.
Number of days in 1 week = 7
Number of weeks she swam = 3
Total number of days she swam = 3 x 7 = 21 days
Distance swam per day = 0.94 km
Total distance swam = Total number of days she swam x Distance swam per day
Total distance swam = 21 x 0.94 = 19.74 km = 19.74 x 1000 m = 19740 m
Distance swam by Sonya in 3 weeks = 19740 m
Answer:
sure (✿^‿^)
Step-by-step explanation:
｡◕‿◕｡
Hi! how are you?
Answer:
79
Step-by-step explanation:
78
---------
7 | 62 03
49
----------
148 | 13 03
11 84
-----------
19
-----------
78^2 = 6084.
We observe that 78^2 < 6203.
79^2 = 6241.
We observe that 79^2 > 6203.
Hence the number to be added to 6203 is 6241 - 6203 = 38.
6203 + 38 = 3241
= 79 * 79
= 79.
Therefore 38 should be added to 6203 to obtain a perfect square.
(32•7a3b2)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "^-4" was replaced by "^(-4)".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
0-(((9•(a2))•(b6))•(0-7ab(-4)))
Step 2 :
Equation at the end of step 2 :
0 - ((32a2 • b6) • -7ab(-4))
Step 3 :
Final result :
(32•7a3b2)
I think its like this ,Tho hope it helped
Answer:20.7
Step-by-step explanation:
