Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer: the hundreds place
Answer:
0.59049
Step-by-step explanation:
Set of all digit strings of length 5
Digit range = (0 - 9) = 10
Length of digit = 5
Total possible outcomes = 10^5 = 100000
String without a 4 ;
Digit range = (0,1,2,3,5,6,7,8,9) = 9
Length of digit = 5
Required outcome = 9^5 = 59049
Required outcome / Total possible outcomes
59049 / 100000
= 0.59049
So you add whats in parentheses first which gives you -11 then you end up with -11(-3)
Which will equal 33 Thats your final awnser...
33
