Hey!
Let p = cost of a pen
<span>Let n = cost of a notebook </span>
<span>The info in the question leads to two equations: </span>
<span>1) 2p + 3n = 5.55 </span>
<span>2) p + 2n = 3.50 </span>
<span>Multiply equation 2) by 2 to get the new system of equations </span>
<span>1a) 2p + 3n = 5.55 </span>
<span>2a) 2p + 4n = 7.00 </span>
<span>Subtract equation 1a) from equation 2a) to get </span>
<span>n = 1.45 ...................... that's the cost of one notebook </span>
<span>~~~~~~~~ </span>
<span>To check, you could go on to figure out p, which turns out to be 0.60 . Put in those values of n and p into the original equations to verify.</span>
Hope this helps! ~Nadia~
Donny drove 70 miles.
Since 60 miles per hour is 1 mile a minute so for in 45 minutes he drove 45 miles. After he drove for 50 miles for thirty minutes so in totally he drove 25 since 50 divided by two is 25.
Answer:
price of gas is $ 3.74 today .
Step-by-step explanation:
A week ago the price of gas was $ 3.40
And it was reported that price of gas is increased by 10 % in the past week.
So the present value of gas =
= 0.34 + 3.40 = $ 3.74 .
So the price of gas is $ 3.74 today .
Answer:
-0.2
Step-by-step explanation:
Simplifying
5x = 3y + -4
Reorder the terms:
5x = -4 + 3y
Solving
5x = -4 + 3y
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Divide each side by '5'.
x = -0.8 + 0.6y
Simplifying
x = -0.8 + 0.6y
Answer:
The probability that the number 7 is one of the numbers drawn is 1/18 or 0.0556.
Step-by-step explanation:
We have on number (7) in 90 possible numbers. There are 5 draws, without replacent.
The number 7 can be drawn in the first, second, third, fourth or fifth draw.
The probability of being picked in the first draw is:

The probability of being picked in the second draw is:

Note: in this case, is the probability of not being picked in the first draw and picked in the second, with one number less (already picked).
The probability of being picked in the third draw is:

The probability is the same for each draw. This can also have been realized by the fact that if the 7 is picked, in any draw, the replacement doesn't matter anymore.
The chances are the sum of the previous ones:
