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Margarita [4]
3 years ago
7

Tom and Diane start to race.Tom took 4 seconds to run 6 yards.Diane ran 5 yards in 3 seconds. If they continued to run at the sa

me speeds,who would get to 30 yards first? Show how you figured out. Who runs faster? How can you compare their speeds?
Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0
\frac{4}{6}= \frac{t}{30}   \\  \\ 120=6t \\  \\ 20=t

It would take Tom 20 seconds.

\frac{3}{5}= \frac{d}{30}   \\  \\ 90=5d \\  \\ d=18

It would take Diane 18 seconds.

Diane would get to 30 yards first.

You can compare their speeds by finding the unit rate. To do this, you have to divide the yards by the seconds.

\frac{6}{4}=1.5 \\  \\  \frac{5}{3}= 1.67

Tom can run 1.5 yards in 1 second and Diane can run 1.67 yards in 1 second.

Diane runs faster.
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3 years ago
Find the value of 7v-10 given that -11v-7=4. Simplify your answer as much as possible.
densk [106]

First thing to do is solve the given equation for v

-11v-7 = 4

-11v = 4+7

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v = 11/(-11)

v = -1

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Answer: -17

4 0
3 years ago
Any volunteer please help
den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

  • The point = (-2, 11)
  • m = 4/3

The point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11)  in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Thus, the equation in the point-slope form is:

y-11=\frac{4}{3}\left(x-\left(-2\right)\right)

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

5 0
3 years ago
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