Answer:
100%
Step-by-step explanation:
Answer: Any real number x as long as and
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Answer:
Step-by-step explanation:
As we can see the given expression as three complex parts and all are being multiplied.
Lets simplify each part separately and then multiply all of them in the end
Part1
Cancelling 8 in numerator with 8 in denominator
Part2
simpliying
Part3
Third part is , and it does not need to be further simplified
Now multiplying all the three parts
So our final answer is
Answer:
The original number is 17.
Step-by-step explanation: