First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Answer:
triangle A= 1/2bh
1/2(18)(14)= 126
semi circle 3.14(9)^2 divided by 2 = 127.17
Triangle Area plus semi circle Area = 126+127.17= 253.17
Answer:
The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?
Step-by-step explanation:
Let y = total charge for a car rental and x = miles driven
Proxy car equation: y = 0.32x + 18
YourPal equation: y = 0.36x + 12
Set equations right sides equal to each other... meaning their cost, y, are equal
0.32x + 18 = 0.36x + 12
18 = 0.04x + 12 (subtract 0.32x from both sides of the equation)
6 = 0.04x (subtract 12 from both sides of the equation)
150 = x (divide both sides of the equation by 0.04)
ANSWER: 150 miles
D bc it needs to have a y intercept of -1
