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forsale [732]
2 years ago
14

Need help with geometry

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
3 0

Answer:

20 degrees, 50 degrees, 80 degrees, 75 degrees, 60 degrees

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4^3 > 6^2 Is this right or not right if not what other sign needs to go there.
Bess [88]

Answer:

that is right

Step-by-step explanation:

because 4×4×4 equals 64 and 6×6 equals 37 so it is 4^3>6^2

6 0
2 years ago
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15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
Tropical forests are being lost at the rate of 5 million hectares per year. how many hectares per day is that? how many hectares
katrin [286]
5,000,000/365= 13,698.630137 hectatres per day /1440 = 9.5129375951388..... hectares per minute

365 days in a year
1440 minutes in a day (24hrs)


7 0
3 years ago
K= 1/2mv^2<br> Solve for V
jeyben [28]

Hi there!

v = ±\sqrt{\frac{2K}{m} }

- - - - - - - - -

K = 1/2mv²

Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):

2 · K = 2 · (1/2mv²)

2K = mv²

Continue isolating by dividing both sides by "m":

2K / m = v²

Take the square root of both sides. Remember that the solution can either be positive or negative since there are positive and negative roots.

v = ±\sqrt{\frac{2K}{m} }

7 0
3 years ago
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To replace a number with another number that tells how many or how much
Papessa [141]
It's subtraction or multiplacation
8 0
3 years ago
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