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mash [69]
3 years ago
7

Celik, S. (2011). A media comparison study on first aid instruction. Health Education Journal. 72(1), 95-101

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

The answer is "Option a".

Step-by-step explanation:

In the given scenario, The appropriate test for the teaching profession's accomplishment pre and post-class would be the two-sample t-test with dependent samples, that's why choice "a" is correct.

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Please help with 7 and 8
Serhud [2]

For #7 - part a: greatest common factor (GCF) is 5.

Part b: cross out everything BUT 10 & 20.

6 0
3 years ago
Read 2 more answers
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
maks197457 [2]
F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =

[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.

g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =

[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.

So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.
5 0
2 years ago
Fwd:The hardware store is having a 15% off sale on lawn mowers this weekend. If x is the original price of a lawn mower, what wi
Sveta_85 [38]

Answer:

<h3>(x - 0.15x) and x(1.00 - 0.15)</h3>

Step-by-step explanation:

Let x be the original price of a lawn mower,

If the hardware store is having a 15% off sale on lawn mowers this weekend, the amount discounted is expressed as;

= 15 % of x

= 0.15 of x

= 0.15x

Final sales price = Original price - discounted price;

Final sales price = x - 0.15x

Factor out x;

x - 0.15x = x(1 - 0.15)

Hence the correct equations are (x - 0.15x)  and x(1.00 - 0.15)

3 0
2 years ago
An investment website can tell what devices are used to access their site. The site managers wonder whether they should enhance
lbvjy [14]

Answer: a)  Unimodal and symmetric

b) 0.26

c) 0.038

Step-by-step explanation:

Given: Sample size of investors (n)= 131

True proportion of smartphone users(p)  =26%

a) Since sampling distribution for the sample proportion is approximately normal when n is larger.

Normal distribution is Unimodal and symmetric.

So correct option : Unimodal and symmetric

b)  mean of this sampling​ distribution = p = 0.26

c)  standard deviation of the sampling​distribution = \sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26\times (1-0.26)}{131}}=\sqrt{0.00146870229008}

=0.0383236518364\approx0.038

6 0
2 years ago
  14.51 less than the product of 26 and x
Mekhanik [1.2K]

<em>the</em><em> </em><em>pro</em><em>duct</em><em> </em><em>of</em><em> </em><em>2</em><em>6</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>wri</em><em>tten</em><em> </em><em>as</em>

<em>2</em><em>6</em><em> </em><em>times</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>6</em><em>x</em>

<em>= 14.51 < 26x</em>

<em>= 1451 \times  {10}^{ - 2}  < 26x</em>

6 0
3 years ago
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