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Kruka [31]
2 years ago
5

A cyclist travels north along a road at a constant speed of 28 miles per hour. At 1:00 P.M., a runner is 68 miles away, running

south along the same road at a constant speed. They pass each other at 3:00 P.M.. What is the speed of the runner?
Mathematics
1 answer:
sergiy2304 [10]2 years ago
4 0

Answer:

The speed of the runner is 6 miles per hour.

Step-by-step explanation:

Given the distance between the cyclist and the runner is 68 miles.

Given the speed of the cyclist is 28 miles per hour.

Initial time is 1:00PM Final time is 3:00PM

Time elapsed is 3-1=2hours

Let the cyclist travel a distance of x miles,Then the distance travelled by the runner is 68-x miles.

speed=\frac{distance}{time}

for the cyclist

28=\frac{x}{2}

x=56 miles

the distance travelled by the runner is 68-56=12 miles

speed of the runner =  12/2 = 6 miles per hour

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Sajia has 30 Books in her library. she sold 9 books at the thrift store on Saturday. Write and solve and inequality to determine
ELEN [110]

Sajia can sell 21 books she can sell if she comes back on sunday and the required inequality is 9 + x \leq 30

<em><u>Solution:</u></em>

Given that Sajia has 30 Books in her library

She sold 9 books at the thrift store on Saturday

To find: We have to write and solve an inequality to determine number of more books she can sell if she comes back on sunday

Let "x" be the number of more books she can sell if she comes back on sunday

<em><u>We can write a inequality as:</u></em>

\text{ books already sold } + \text{ number of books remaining } \leq \text{ total number of books she has }

9 + x \leq 30

Now moving 9 from L.H.S to R.H.S we get,

x \leq 30 - 9

On solving 30 - 9 = 21,

x \leq 21

So Sajia can sell 21 books she can sell if she comes back on sunday

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2 years ago
There are 10 fishes 2 drown 1 runs away and 5 died how many fishes are left?
dezoksy [38]
There are still 10 fish but only 5 are alive because fish don't drown
3 0
2 years ago
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How is the pattern changing to get from one term to the next? 55, 49, 43, 37, 31,...
ZanzabumX [31]

Answer:

C.

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2 years ago
Construct 3 linear equation starting with qiven solution z = 1/3
Andreyy89

Answer:

(a)9z+2=5

(b)21z-11=-4

(c)4z=2-2z

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

<u>Equation 1</u>

<u />z=\frac{1}{3}<u />

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9z=\frac{1}{3}\times 9\\9z=3

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Add 2 to both sides

Our first equation is: 9z+2=5

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Rewrite 7 as 11-4

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Subtract 11 from both sides

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Multiply both sides by 6

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Rewrite 6z as 4z+2z

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3 years ago
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