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Kruka [31]
3 years ago
5

A cyclist travels north along a road at a constant speed of 28 miles per hour. At 1:00 P.M., a runner is 68 miles away, running

south along the same road at a constant speed. They pass each other at 3:00 P.M.. What is the speed of the runner?
Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

The speed of the runner is 6 miles per hour.

Step-by-step explanation:

Given the distance between the cyclist and the runner is 68 miles.

Given the speed of the cyclist is 28 miles per hour.

Initial time is 1:00PM Final time is 3:00PM

Time elapsed is 3-1=2hours

Let the cyclist travel a distance of x miles,Then the distance travelled by the runner is 68-x miles.

speed=\frac{distance}{time}

for the cyclist

28=\frac{x}{2}

x=56 miles

the distance travelled by the runner is 68-56=12 miles

speed of the runner =  12/2 = 6 miles per hour

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Factor this polynomial completely x2 + 3x – 18 A. (x-2)(x + 9) B. (x+3)(x-6) оо C. (x - 3)(x+6) D. (x - 3)(x-6)​
Umnica [9.8K]

Answer:

C. (x-3)(x+6)

Step-by-step explanation:

I think the equation meant x^2+3x-18?

Anyways, to factor these kinds of quadratic, keep into consideration:

ax^2+bx+c=(x+w)(x+v)

ONLY if:

w+v=b\\wv=c

Start off by finding factors of c, which in this case, -18:

±(1, 2, 3, 6, 9, 18)

If one of the numbers is negative then the other number must be positive.

Find which two factors will sum up to b, which in this case, is 3.

1+(-18)\neq 3\\2+(-9)\neq 3\\3+(-6)\neq 3\\6+(-3)=3\\9+(-2)\neq 3\\18+(-1)\neq 3\\

The only two factors that work are 6 and -3.

Replace them into the factored form:

(x+w)(x+v)\\(x+6)(x-3)\\(x-3)(x+6)

3 0
2 years ago
Read 2 more answers
Create a polynomial function in standard form with a leading coefficient of 2 and zeros at 0 1 and 3 brainly
TEA [102]

Answer:

P(x) = 2x^3 - 8x^2 + 6x

Step-by-step explanation:

Given

p =2 -- Leading coefficient

Zeros: 0, 1\ and\ 3

Required

Determine the polynomial

Represent the zeros with a, b and c.

Such that

a = 0

b = 1

c = 3

The polynomial is:

P(x) = p * (x - a) * (x - b) * (x - c)

P(x) = 2 * (x - 0) * (x - 1) * (x - 3)

P(x) = 2x * (x - 1) * (x - 3)

Open bracket

P(x) = (2x^2 - 2x) * (x - 3)

P(x) = 2x^3 - 6x^2 - 2x^2 + 6x

P(x) = 2x^3 - 8x^2 + 6x

5 0
3 years ago
Find the slope of the line through the points (4,-4) and (9,-4).
Dahasolnce [82]

Answer:

0

Step-by-step explanation:

We have two points we can use the slope formula

m = (y2-y1)/(x2-x1)

     = (-4 - -4)/(9-4)

    (-4+4)/(9-4)

     0/5

   =0

3 0
3 years ago
A surveyor is conducting measures to see how wide a road is
drek231 [11]

Answer:

D) 45 ft

Step-by-step explanation:

The two triangles are shown below.

Given:

BC = 60 ft, CD = 24 ft and DE = 18 ft.

Since, the two triangles are similar, their corresponding sides are in proportion.

So, \frac{AB}{DE}=\frac{BC}{CD}=\frac{AC}{CE}

Now, consider the proportion of sides,

\frac{AB}{DE}=\frac{BC}{CD}\\AB=\frac{BC}{CD}\times DE\\AB=\frac{60}{24}\times 18\\AB=\frac{60\times 18}{24}=45\ ft

Therefore, the distance between A and B is 45 ft.

8 0
3 years ago
Pls help to write an equation
sineoko [7]
6 - (-5)
it went 11 feet
6 0
3 years ago
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