The first trigonometric expression cot x and sin x in terms of the second expression is one over tan x and one over cosec x.
<h3>What is trigonometry?</h3>Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.
Write the first trigonometric expression in terms of the second expression.
The cotangent can be written as
And the sine can be written as
More about the trigonometry link is given below.
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Answer:
-7
Step-by-step explanation:
Refer to the photo.
the slope=(0-g)/(5-4)
i.e. 7=(-g)/1
g=-7
Hi there!
We can calculate dy/dx using implicit differentiation:
xy + y² = 6
Differentiate both sides. Remember to use the Product Rule for the "xy" term:
(1)y + x(dy/dx) + 2y(dy/dx) = 0
Move y to the opposite side:
x(dy/dx) + 2y(dy/dx) = -y
Factor out dy/dx:
dy/dx(x + 2y) = -y
Divide both sides by x + 2y:
dy/dx = -y/x + 2y
We need both x and y to find dy/dx, so plug in the given value of x into the original equation:
-1(y) + y² = 6
-y + y² = 6
y² - y - 6 = 0
(y - 3)(y + 2) = 0
Thus, y = -2 and 3.
We can calculate dy/dx at each point:
At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.
At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.