C.) 3:5 = 12:20
It is this because you can divide them evenly into each other. 3*4 is 12 and if you do 5*4 it is 20. Boo yeah
Answer:
-1
Step-by-step explanation:
Has to be the opposite
Answer:
i thinks the answer of that is letter A
Answer:
1.5.80 miles
2.9.80ft
3.56 inches
4.5.20 units
5. 13 units
6.5.40 ft
Step-by-step explanation:
⇒These questions are on the Pythagorean relationship
⇒General expression is ;
a²+b²=c² where a and b are values for the legs and c is the hypotenuse
1. Isaiah waked 3 miles north and 5 miles east.
Finding the distance from starting point we apply the equation;
a²+b²=c² where a=5 miles and b=3miles
5²+3²=c²
25+9=c²
34=c²
c=√34 = 5.80 miles
2.The ladder is leaning against the wall to form the hypotenuse side of 10 ft.The distance from the base to the ladder forms side a= 2ft. The question requires you to calculate the height b.
a²+b²=c²
2²+b²=10²
4+b²=100
b²=100-4
b=√96
b=9.80 ft
3. The television has a diagonal of 70 inches to represent side c and a height of 42 inches to represent the side a. The question requires you to find the width of the television which represents the side b
a²+ b²=c²
42²+b²=70²
b²=70²-42²
b=√3136
c=56 inches
4. An equilateral triangle is one that has all its sides and angles equal. Here you have to introduce a perpendicular line from the apex point of the triangle to the base and get the distance a.The using the hypotenuse and the distance a, you can find the height/b.
c= 6 units and a=6/2= 3 units
a²+b²=c² 3²+ b²= 6²
9+b²=36
b²=36-9
b=√27 =5.20 units
5.In this question, you are given the height and the width of the right triangle thus apply the relationship as;
a²+b²=c²..........where a=5 and b=12
5²+12²=c²
25+144=c²⇒⇒⇒c=√169 =13 units
6. In this question, the height of the plant represents side b and the distance of the base from where the string is tied is side b.You are to find the length of the string which represents the hypotenuse side.
a²+b²=c²
5²+2²=c²
25+4=c²
29=c²
√29=c
c=5.40 ft
Answer:
A.
Step-by-step explanation:
you have to find the discriminant
b²-4ac for each equation
if discriminant < 0 no real solutions because will be negative under the squareroot whhan you try to find the roots
if discriminant = 0 there is only one solution
if discriminant > 0 two real solutions
for your given problems
A. discriminant =(-2)²-4*2*15 will be negative
