Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


The further left a number is the less it is
The further right a number is the greater it is
Answer:

Step-by-step explanation:
We can use substitution to find the value of
:




Hope this helps :)
Answer:
Shown - See explanation
Step-by-step explanation:
Solution:-
- The given form for rate of change is:
8 sec(x) tan(x) − 8 sin(x).
- The form we need to show:
8 sin(x) tan2(x)
- We will first use reciprocal identities:

- Now take LCM:

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

Answer:
the answer is this
Step-by-step explanation:
To calculate the break-even point in units use the formula: Break-Even point (units) = Fixed Costs ÷ (Sales price per unit – Variable costs per unit) or in sales dollars using the formula: Break-Even point (sales dollars) = Fixed Costs ÷ Contribution Margin