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3 years ago

Anyone help me pzzzzzzzzz

Mathematics

1 answer:

Marina86 [1]3 years ago

4 0

The x values are the domain and they y values are the range. So the domain is {-2, 0, 2}. And the range is {-1, 0, 1}. So B is the answer.

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A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched

Bad White [126]

$\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta = 80\\
r=26
\end{cases}\implies s=\cfrac{80\cdot \pi \cdot 26}{180}$

8 0

3 years ago

Please!!! I’ll mark Brainliest!! I really need help!!!

Tatiana [17]

Answer:

$(x, \: \: y) = (4, \: \: - \frac{1}{4} )$

Step-by-step explanation:

$\frac{1}{4} x + \cancel{ 1 \frac{1}{2} y} = \frac{5}{8}...(1) \\ \\ \frac{3}{4} x - \cancel{ 1 \frac{1}{2} y} = 3 \frac{3}{8} ...(2) \\ - - - - - - - - - \\(adding\: equations\: 1 \:\&\:2) \\ ( \frac{1}{4} + \frac{3}{4} )x = \frac{5}{8} + 3 \frac{3}{8} \\ \\ \frac{4}{4} x = \frac{5}{8} + \frac{27}{8} \\ \\ x = \frac{32}{8} \\ \\ x = 4 \\ \\ plug \: x = 4 \: in \: equation \: (1) \\ \\ \frac{1}{\cancel 4} \times \cancel 4 + 1 \frac{1}{2} y = \frac{5}{8} \\ \\ 1 + \frac{3}{2} y = \frac{5}{8} \\ \\ \frac{3}{2} y = \frac{5}{8} - 1\\ \\ \frac{3}{2} y = \frac{5 - 8}{8}\\ \\ \frac{3}{2} y = \frac{ - 3}{8}\\ \\ y = \frac{ - 3}{8} \times \frac{2}{3} \\ \\ y = \frac{1}{4} \\ \\ (x, \: \: y) = (4, \: \: - \frac{1}{4} )$

5 0

2 years ago

AB = x - 10, BC = x + 2, and AC = 28. Find BC.<br><br>Please help!

Leno4ka [110]

Answer:

BC = 20

Step-by-step explanation:

AC = AB + BC

28 = x-10 + x+2

Combine like terms

28 = 2x -8

Add 8 to each side

28+8 = 2x-8+8

36 = 2x

Divide by 2

36/2 = 2x/2

18 =x

We want to find BC

BC = x+2

=18+2

=20

6 0

3 years ago

Read 2 more answers

Help I mark brainliest

Serga [27]

Answer:

$-\frac{1}{5} t^{15}$

Step-by-step explanation:

sry if im wrong

3 0

3 years ago

Can someone help me please

babunello [35]

If the functions are inverses, then f(g(x)) = x.

$\displaystyle f(g(x))=f\left(\frac{3x+1}{3}\right)=\frac{1}{\frac{3x+1}{x}-3}\\\\=\frac{1}{\left(\frac{3x+1-3x}{x}\right)}=\frac{1}{\left(\frac{1}{x}\right)}=x$

The functions are inverses of each other.

B. The domain of f(x) = x≠3. The domain of g(x) is x≠0.

The domain of f(g(x)) is (-∞, 0) ∪ (0, ∞).

The domain of g(f(x)) is (-∞, 3) ∪ (3, ∞).

4 0

3 years ago