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8090 [49]
3 years ago
14

Plz help ASAP !!!!! Plzzz

Mathematics
1 answer:
adell [148]3 years ago
5 0

Answer:

The second one

Step-by-step explanation:

She started with x dollars and then used 8 dollars to buy a football game ticket, so x-8. Then, she is left with 56 dollars, so x-8=56. Therefore, the second story represents the equation.

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Find the solution to this system of equations <br> 3x+2y+3z=3 4x-5y+7z=1 2x+3y-2z=6 <br> x=? Y=? Z=?
Ede4ka [16]

Answer:

The solution is x=2,\ y=0,\ z=-1.

Step-by-step explanation:

You are given the system of three equations:

\left\{\begin{array}{l}3x+2y+3z=3\\4x-5y+7z=1\\2x+3y-2z=6\end{array}\right.

Multiply the first equation by 4, the second equation by 3 and subtract them. Then multiply the third equation by 2 and subtract it from the second equation:

\left\{\begin{array}{l}3x+2y+3z=3\\4(3x+2y+3z)-3(4x-5y+7z)=4\cdot 3-3\cdot 1\\4x-5y+7z-2(2x+3y-2z)=1-2\cdot 6\end{array}\right.\Rightarrow \\\\\left\{\begin{array}{l}3x+2y+3z=3\\12x+8y+12z-12x+15y-21z=12-3\\4x-5y+7z-4x-6y+4z=1-12\end{array}\right.

So,

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\-11y+11z=-11\end{array}\right.\Rightarrow \left\{\begin{array}{l}3x+2y+3z=3\\23y-9z=9\\y-z=1\end{array}\right.

Multiply the third equation by 23 and subtract it from the second equation:

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23(y-z)=9-23\cdot 1\end{array}\right.\Rightarrow \left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23y+23z=9-23 \end{array}\right.

Hence,

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\14z=-14 \end{array}\right.\Rightarrow z=-1

Substitute it into the second equation:

23y-9\cdot (-1)=9\Rightarrow 23y+9=9\\ \\23y=0\\ \\y=0

Substitute them into the first equation:

3x+2\cdot 0+3\cdot (-1)=3\Rightarrow 3x-3=3\\ \\3x=6\\ \\x=2

The solution is x=2,\ y=0,\ z=-1.

3 0
3 years ago
I don’t know how to do this
Rina8888 [55]
Slope is .5/5
B) the longer you talk on the phone, the more it’s going to cost
C) .50 cents
D)30 minutes
5 0
3 years ago
Question 4 (2 points)
Svetradugi [14.3K]

Answer:

1. sometimes true

A rhombus is a quadrilateral with all equal size and length. A square is a quadrilateral with all equal size and length, and all right angles around bus, however, can be a square if it has right angles.

2. always true

A square has to have all equal sides and all right angles, however, a rectangle has to have right angles and opposite sides are equal to each other. So if a square has equal sides, it can be considered a rectangle since both opposite sides are equal

3. sometimes true

A parallelogram is a quad roulette or with parallel and equal opposite sides, and a rectangle has right angles and equal opposite sides, therefore, if the parallelogram has right angles, then it is considered a rectangle

4. always true

A quadrilateral has to have 4 sides and the rectangle has 4 sides there, for it is considered a quadrilateral

5. never true

A parallelogram is a quadrilateral, therefore, it has to have 4 sides, but a hexagon has to have 6 sides, therefore, it is never a hexagon

5 0
3 years ago
Hey:) can you please help me posted picture of question
Elina [12.6K]
Answer:
10x⁴ - 33x² - 7

Explanation:
Before we begin, remember the following:
xᵃ * xᵇ = xᵃ⁺ᵇ

Now, for the given:
To solve the given question, we will multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final expression.

This can be done as follows:
(5x² + 1)(2x² - 7)
5x²(2x²) + 5x²(-7) + 1(2x²) + 1(-7)
10x⁴ - 35x² + 2x² - 7
10x⁴ - 33x² - 7

Hope this helps :)
3 0
3 years ago
I need the work!and i don’t understand plz help!
Ket [755]

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

8 0
3 years ago
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