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2 years ago

The ratio of girls to boys in a class is 4:3. If the total number of students in the class are 28. How many of them are girls?

Mathematics

1 answer:

Olegator [25]2 years ago

7 0

4x + 3x = 28

7x = 28

7x/7 = 28/7

X = 4

Girls = 4

4x4 = 16

16 girls

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Answer:

Cos θ = √7/3

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine θ = √2 / 3

Cos θ =?

Recall

Sine θ = Opposite / Hypothenus

Sine θ = √2 / 3

Thus,

Opposite = √2

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Next, we shall determine the Adjacent. This can be obtained as follow:

Opposite = √2

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Adjacent =?

Hypo² = Adj² + Opp²

3² = Adj² + (√2)²

9 = Adj² + 2

Collect like terms

9 – 2 = Adj²

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Take the square root of both side

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3 years ago

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A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

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$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

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