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Anika [276]
3 years ago
14

What is the slope and what does the slope represent in this context? *

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

plssss

Step-by-step explanation:

i need your help to answer my module plsss :(

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A piece of cardboard is 24 centimeters long and 15 centimeters wide. What is the area?
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24*15=

360

360 square centimeters
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all real numbers greater than or equal to -1

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What is the solution to the inequality -3x - 42 > 3
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I don’t know which answer choice it is since C and D are the same but the answer is supposed to be x < -15.

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2 years ago
Given that sec (x) = 2 and cosec (x) is negative,
weeeeeb [17]

Answer:

i) sin(2x) = -\frac{\sqrt{3}}{2}

ii) cot(x+360) = -\frac{\sqrt{3}}{3}

iii) sin(x-180) = \frac{\sqrt{3}}{2}

Step-by-step explanation:

sec(x) = 2

Since cos(x) is reciprocal of sec(x), this means:

cos(x) = \frac{1}{2}

cosec(x) is negative , this means sin(x) is also negative. The only quadrant where cos(x), sec(x) are positive and sin(x), cosec(x) are negative is the 4th quadrant. Hence the terminal arm of the angle x is in 4th quadrant.

Part i)

sin(2x) can be simplified as:

sin(2x) = 2 sin(x) cos(x)

First we need to find the value of sin(x). According to Pythagorean identity:

sin^{2}(x)=1-cos^{2}(x)\\\\ sin(x)=\pm \sqrt{1-cos^{2}(x)}

Since, angle is in 4th quadrant, sin(x) will be negative. So considering the negative value of sin(x) and substituting the value of cos(x), we get:

sin(x)=- \sqrt{1-cos^{2}(x)}\\\\ sin(x)=-\sqrt{1-(\frac{1}{2})^{2}}\\\\ sin(x)=-\frac{\sqrt{3}}{2}

So,

sin(2x)=2 \times -\frac{\sqrt{3} }{2} \times \frac{1}{2}\\\\ sin(2x)=-\frac{\sqrt{3}}{2}

Part ii)

We have to find cot(x + 360)

An addition of 360 degrees to the angle brings it back to the same terminal point. So the trigonometric ratios of the original angle and new angle after adding 360 or any multiple of 360 stay the same. i.e.

cot(x + 360) = cot(x)

cot(x) = \frac{cos(x)}{sin(x)}\\

Using the values, we get:

cot(x)=\frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2} }\\\\ cot(x)=-\frac{\sqrt{3}}{3}

Part iii)

We need to find the value of sin(x - 180)

sin(x - 180) = - sin(x)

Addition or subtraction of 180 degrees changes the angle by 2 quadrants. The sign of sin(x) becomes opposite if the angle jumps by 2 quadrants. For example, sin(x) is positive in 1st quadrant and negative in 3rd quadrant.

So,

sin(x - 180) = -(-\frac{\sqrt{3}}{2}) = \frac{\sqrt{3}}{2}

6 0
3 years ago
Determine whether the triangles are similar. If so, write a similarity statement and name the postulate or the theorem you used.
neonofarm [45]
The first pair of triangles are similar.

Triangle ABC is similar to Triangle PQR.

I used the SSS theorem of congruency.

( side - side - side) since I knew the sides were equal I knew that they were congruent.

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The second pair of triangles are similar too.

Triangle ABC is similar to Triangle DEF.

I also used the SSS theorem of congruency.

Since I knew what the sides were, I did some calculations and they all equalled 6...

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I hope that helps you out!! Any more questions??
6 0
3 years ago
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