Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Suppose x quarts of the 50% solution
0.5x+0.2*20=0.4(x+20)
0.5x+4=0.4x+8
0.1x=4
x=40
Answer: 40
Step-by-step explanation:
Y=-2x+2 and y=x^2-3x.
If there are solutions the x and y values are equal so we can say y=y:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 now factor...
x^2+x-2x-2=0
x(x+1)-2(x+1)=0
(x-2)(x+1)=0
So there are two solutions, when x=-1 and 2
Using y=-2x+2 we can find the corresponding y values for the solutions...
y(-1)=-2(-1)+2=2+2=4, y(2)=-2(2)+2=-4+2=-2 so the two solutions are the points:
(-1,4) and (2,-2)
Answer:
x = 2 and y = 
Step-by-step explanation:
To solve this system of equation, we will follow the steps below;
We will use both elimination and substitution method to solve this system of equations
12x−15y=14 ------------------------------------------------------------------------(1)
8x−15y=6 --------------------------------------------------------------------------(2)
subtract equation (2) from equation (1)
(By doing that the y variable will be eliminated)
4x = 8
Divide both-side of the equation by 4
4x/4 = 8/4
x = 2
Substitute x =2 into equation (2) and then solve for y
8x−15y=6
8(2)−15y=6
16 - 15y = 6
subtract 16 from both-side of the equation
16 - 16- 15y = 6-16
-15y = -10
Divide both-side of the equation by -15
-15y/-15 = -10/-15
y =
x = 2 and y =
