I'll explain how to do the first one:-
y = cos-1(x2)
This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.
We need to apply the chain rule.
Personally I find this easier to understand if i let u = x^2, so
If y = f(u) and u is a function of x then
dy/dx = dy/ du * du/dx
Here u = x^2 and y = cos-1(u)
du/dx = 2x
so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx
= -1 / √(1 - u^2) * 2x
= -2x / √(1 - u^2)
= -2x / √(1 - (x^2)^2)
= -2x / √(1 - x^4)
I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.
Answer:
a / (a - 4) = a(a + 4) / ((a - 4)(a + 4)) = (a^2 + 4a) / (a^2 - 16) = -(a^2 + 4a) / (16 - a^2)
Step-by-step explanation:
so go to safari and look it up !!!
Answer:
<em>Gerry arrived at the bus station at 12:30 P.M.</em>
Step-by-step explanation:
From noon and 5:00 P.M. there are 5 hours.
Gerry, Dale, and Pat arrived at the bus stop within that interval, which means the sum of the times elapsed between their arrival times must be 5.
4 out of the 5 hours elapsed since Gerry and Dale's arrivals. This means there is only one hour left for twice x.
If twice x is one hour, then x is half an hour. Thus, the complete sequence of arrivals is:
Gerry arrived at the bus station at 12:30 P.M.
Dale arrived at the bus station at 4:30 P.M.
Pat arrived at the bus station at 5:00 P.M.
Do you mean the phythagorus theorum: a squared + b squared= c squared
