Answer:
Answer: x= -6 and y= -7
Step-by-step explanation:
Substitute 2x+5 for y in y=3x+11:
y=3x+11
2x+5=3x+11
2x+5+−3x=3x+11+−3x(Add -3x to both sides)
−x+5=11
−x+5+−5=11+−5(Add -5 to both sides)
−x=6
−x−1=6−1(Divide both sides by -1)
x=−6
Step: Substitute −6 for x in y=2x+5:
y=2x+5
y=(2)(−6)+5
y=−7(Simplify both sides of the equation)
-Source: MathPapa
4 to the 1st is 4
4 to the 2nd is 16
4 to the 3rd is 64
<span>4 to the 4th is 256</span>
You find the eigenvalues of a matrix A by following these steps:
- Compute the matrix
, where I is the identity matrix (1s on the diagonal, 0s elsewhere) - Compute the determinant of A'
- Set the determinant of A' equal to zero and solve for lambda.
So, in this case, we have
![A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Cimplies%20A%27%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1-%5Clambda%26-2%5C%5C-2%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D)
The determinant of this matrix is
Finally, we have
So, the two eigenvalues are
Answer:
0.16
Step-by-step explanation:
Given the data:
Students __ `Gr_9 __Gr_10 __ G_11 __G_12
Frequency : 152 ___130 ______ 80 ___98
The probability is :
Frequency of grade 11 / number of trials
80 / 500
2^2 X 19 is the prime factorization of 76
