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Kazeer [188]
3 years ago
7

All changes

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

21

Step-by-step explanation:

Volume= (4/3)*pi*r^3

40007= (4/3)*pi*r^3

r=21m

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8 - 3m = 2m<br><br>please help step by step standard form
Pepsi [2]

Answer:

m = 8/5 or  1   3/5

Step-by-step explanation:

8 - 3m = 2m

add 3m to each side

8 - 3m+ 3m = 2m+ 3m

8 = 5m

divide by 5 on each side

8/5 = 5m/5

8/5 = m


4 0
4 years ago
Read 2 more answers
a baby blue whale weighed 5200 lbs birth. after 2 days the baby weighed 5710. after 14 days the baby weighed 8180 lbs is it prop
sveticcg [70]

Answer:

NOPE

Step-by-step explanation:

6 0
3 years ago
There are two fruit trees located at (3,0) and (–3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the f
Mama L [17]
Maurice wants to create a set of elliptical flower beds. To do this, he first plots the location of the two fruit trees on his graph.

Maurice has to use the equation a^2-b^2=c^2. We know that c=3, and because we need 1 more number to solve for b, I made a=6. 6^2-b^2=3^2. 36-b^2=9. b^2=27. b=5.196

<span>Next, to create the equation, we substitute what we know into the equation x^2/a^2 + y^2/b^2=1 and get x^2/36 + y^2/27=1. Johanna wants to create some hyperbolic flower beds.

We already know that c=3 so this time I decided a=1. 3^2=1^2+b^2. 9=1+b^2. 8=b^2. b=2.828
 
Next, to create the equation, we substitute what we know to the equation x^2/a^2 - y^2/b^2 = 1. x^2/1^2 - y^2/2.828^2 = 1. </span>
3 0
3 years ago
The average annual salary for employees in a store is $50,000. It is given that the population standard deviation is $4,000. Sup
Nadya [2.5K]

Answer: 478

Step-by-step explanation:

The formula to calculate the standard error of the population mean is given by :-

S.E.=\dfrac{\sigma}{\sqrt{n}}, where \sigma is the standard deviation and 'n' is the sample size.

Given: Mean : \mu=$\50,000

Standard deviation : \sigma= $\4,000

Sample size : n=70

Now, the value of the standard error of the average annual salary is given by :-

S.E.=\dfrac{50000}{\sqrt{70}}=478.091443734\approx478

Hence, the standard error of the average annual salary = 478

5 0
3 years ago
What would you write for the rang of this graph
VladimirAG [237]

The range of any graph are the set of all the y-values of the graph. For this graph, it goes all the way from 0 to about 3.5. I'd say the range of this graph was {0, 3.5}. Hope I could help!

6 0
3 years ago
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