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3 years ago

7

Juan will put fencing around the outside of the enclosure. How much fencing does he need for the enclosure?

1 answer:

adell [148]3 years ago

3 0

If Juan intends to put fencing around the enclosure, that means that we are looking at the perimeter of the image (the outside). We can count the amount of lines between the dots to determine how much fencing he will need. After counting the perimeter of this figure, we see that the total is 22. We do not know what the units are, so for now we can just say that he will need 22 units of fencing to fully enclose this shape.

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A circular mirror is surrounded by a metal frame. The radius of the mirror is 2x. The side length of the metal frame is 12x. Wha

meriva

Answer:

$Area\ of\ th\e metal\ frame = 65.5x^{2}\ (unit)^{2}$

Step-by-step explanation:

Assuming that the metal frame is a square metal frame because the length of the side of the metal frame is given.

Given:

Radius of the mirror = 2x unit

Side length of the square metal frame = 12x unit

We need to find the area of the metal frame.

Solution:

First we find the area of the circular mirror, using area formula of the circle.

$A_{c} = \pi r^{2}$

Where, r = Radius of the object.

Substitute r = 2x in above equation.

$A_{c} = \pi (5x)^{2}$

$A_{c} = \pi (25x^{2})$

$A_{c} = 25\pi x^{2}\ (unit)^{2}$

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$A_{S} = (Side\ length)^{2}$

$A_{S} = (12x)^{2}$

$A_{S} = 144x^{2}\ (unit)^2}$

So, the area of the square metal frame is given as

$A_{f}=A_{s}-A_{c}$

$A_{f}=144x^{2}-25\pi x^{2}$

$A_{f}=(144-25\pi) x^{2}$

$A_{f}=(144-25\times 3.14) x^{2}$

$A_{f}=(144-78.5) x^{2}$

$A_{f}=65.5 x^{2}\ (unit)^{2}$

Therefore, the area of the metal frame is $65.5x^{2}\ (unit)^{2}$ .

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