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nata0808 [166]
3 years ago
9

Match the planet to its description.

Chemistry
2 answers:
sp2606 [1]3 years ago
5 0

Explanation:

venus

earth

mars

mercury

dem82 [27]3 years ago
4 0
Venus
Earth
Mars
Mercury
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What is the molecular formula for chloroform? none of these choices CH3C CHCI3 CH2C12 CCI4
dangina [55]

Answer:

CHCI₃

Explanation:

Chloroform, IUPAC name, trichloromethane, is organic compound with the molecular  formula CHCl₃. It is colorless and sweet-smelling liquid having high density which is produced on a large scale precursor of PTFE , and for various refrigerants .

Chloroform , is a powerful euphoriant , anxiolytic , anesthetic and sedative when inhaled or ingested .

4 0
3 years ago
7. Which of the following represents the largest mass?
Tamiku [17]

Answer:

 10kg = 10 x 1000 = 10,000g

Explanation:

To know the quantity with the largest mass, we have to express all the units in grams:

for: 2 x 10mg = 2 x 10 x 10⁻³ = 0.02g

       0.001kg = 0.001 x 1000 = 1g

       1 x 10⁵ng = 1 x 10⁵ x 10⁻⁹ = 0.0001g

       2 x 10²cg = 2 x 10² x 10⁻² = 2g

       10kg = 10 x 1000 = 10,000g

Note:

              10⁻ ¹      deci(d)

              10⁻²       centi(c)

              10⁻³       milli(m)

            10⁻⁹         nano(n)

            10³           kilo(k)

   

5 0
4 years ago
The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?
n200080 [17]

<u>Answer:</u> The moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of atmosphere = 5.00\times 10^{18}kg=5.00\times 10^{21}g

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = \frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol

Moles of carbon dioxide in air = \frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol

Hence, the moles of oxygen and carbon dioxide in air is 3.63\times 10^{19}mol and 7.18\times 10^{16}mol respectively

6 0
3 years ago
Students in a chemistry class are drawing molecular models based on molecular formulas they are given by the teacher.
Karo-lina-s [1.5K]
Sorry I need this marks
5 0
3 years ago
Which characteristic might identify a substance as an Arrhenius base?
Scorpion4ik [409]

Answer: a

Explanation: because an Arrhenius acid is a compound that increases the H + ion concentration in aqueous solution. An Arrhenius base is a compound that increases the OH − ion concentration in aqueous solution.

5 0
4 years ago
Read 2 more answers
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