Answer:
Ka = 3.50x10⁻⁴
Explanation:
First, we need to convert the unit of 3.60 g/L to mol/L:
The reaction dissociation of aspirin in water is:
C₉H₈O₄ + H₂O ⇄ C₉H₇O₄⁻ + H₃O⁺
0.02 - x x x
The constant of the above reaction is:
![Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]}](https://tex.z-dn.net/?f=%20Ka%20%3D%20%5Cfrac%7B%5BC_%7B9%7DH_%7B7%7DO_%7B4%7D%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BC_%7B9%7DH_%7B8%7DO_%7B4%7D%5D%7D%20)
To find Ka we need to find the value of x. We know that pH = 2.6 so:
![pH = -log[H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20)
![x = 2.51 \cdot 10^{-3} M = [H_{3}O^{+}] = [C_{9}H_{7}O_{4}^{-}]](https://tex.z-dn.net/?f=%20x%20%3D%202.51%20%5Ccdot%2010%5E%7B-3%7D%20M%20%3D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%5BC_%7B9%7DH_%7B7%7DO_%7B4%7D%5E%7B-%7D%5D%20)
Now, the concentration of C₉H₈O₄ is:
Finally, Ka is:
![Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]} = \frac{(2.51 \cdot 10^{-3})^{2}}{0.018} = 3.50 \cdot 10^{-4}](https://tex.z-dn.net/?f=%20Ka%20%3D%20%5Cfrac%7B%5BC_%7B9%7DH_%7B7%7DO_%7B4%7D%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BC_%7B9%7DH_%7B8%7DO_%7B4%7D%5D%7D%20%3D%20%5Cfrac%7B%282.51%20%5Ccdot%2010%5E%7B-3%7D%29%5E%7B2%7D%7D%7B0.018%7D%20%3D%203.50%20%5Ccdot%2010%5E%7B-4%7D%20)
Therefore, the Ka of aspirin is 3.50x10⁻⁴.
I hope it helps you!
Answer:
As soon as a front passes a particular location, the weather could change from a steamy maritime tropical air mass to a dry.
Explanation:
hope this helps
<h3>
Answer:</h3>
1.1 × 10²² atoms Au
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.7 g Au
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Au - 196.97 g/mol
<u>Step 3: Convert</u>
<u />
= 1.13121 × 10²² atoms Au
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
1.13121 × 10²² atoms Au ≈ 1.1 × 10²² atoms Au
21) Ionic
22) Ionic
23) Covalent
24) Ionic ?
25) Ionic
26) Ionic
27) Ionic ?
28) Covalent
29) Ionic ?
30) Covalent
31) Ionic ?
32) Ionic ?
33) Covalent
34) Ionic ?
35) Ionic ?
36) Covalent ?
37) Covalent
38) Ionic ?
39) Ionic ?
40) Covalent
These answers are based on if there was a nonmetal and nonmetal it’s Covalent and if there was a metal and nonmetal it was Ionic I didn’t use the electro negativity for the answers that has more than two elements, if the answers had more than two elements they have a ? Next to their answer.
I HOPE THIS HELPS AND IF IM WRONG FEEL FREE TO COMMENT AND TELL ME SO
