Question

Consider the reaction, 2 d(g) + 3 e(g) + f(g) => 2 g(g) + h(g) when h is increasing at 0.64 mol/ls, how quickly is e decreasing? give your answer to 3 decimal places.

Answer 1

Answer is: 1,92 mol/L·s.
Chemical reaction: 2D(g) + 3E(g) + F(g) → 2G(g) + H(g). 
H is increasing at 0,64 mol/L·s.
From chemical reaction n(H) : n(E) = 1 : 3.
0,64 mol : n(E) = 1 : 3.
n(E) = 1,92 mol.
E is decreasing at 1,92 mol/L·s.