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DiKsa [7]
3 years ago
5

Yooo i need help please no fakes!!

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

260

Step-by-step explanation:

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Is this right pls...
Dmitry [639]
Yuppp, it is correct!
6 0
3 years ago
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1 point) during a winter season at one ski resort, there are two roads from area a to area b and two roads from area b to area
miss Akunina [59]
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)

Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
5 0
4 years ago
Which two answer options describe a correct way to solve this problem?
olya-2409 [2.1K]
The answer is B) add 1.25 and 2.70 and subtract that from 10.00
4 0
3 years ago
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Suppose you are managing 15 employees, and you need to form three teams to work on different projects. Assume that all employees
Afina-wow [57]

Answer:

There are 17,418,240 different ways to choose the teams.

Step-by-step explanation:

Arrangements of n elements:

The number of possible arrangements of n elements is given by:

A_{n} = n!

In how many different ways can the teams be chosen so that the number of employees on each project are as follows: 9, 4, 2?

This is:

Arrangement of 9 elements, followed by an arrangement of 4 elements followed by an arrangement of 2 elements. So

T = A_{9}*A_{4}*A_{2} = 9!*4!*2! = 362880*24*2 = 17418240

There are 17,418,240 different ways to choose the teams.

7 0
3 years ago
Add:
dezoksy [38]
   (4-3n-5n2)

+( -2+n-3n2)
____________________
    -2-2n-8n2

8 0
3 years ago
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