Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
To solve this we need to form 2 equations with only 2 variables.
x+4y-5z=-7
2x+y+5z=8
3x+5y=1
15x+10y+15z=35
6x+3y+15z=24
9x+7y=11
Now we need to use these to find x and y
9x+15y=3
9x+7y=11
8y=-8
y=-1
Therefore:
x=2
From this we can find that:
2(2)-1+5z=8
Therefore z=1
The answer is x=2, y=-1, z=1
Answer: taake this link, it has all the answers
Step-by-step explanation: https://quizlet.com/183183758/statistical-studies-scatterplots-practiceamdm-flash-cards/
Answer: it equals 20
Step-by-step explanation:
10 x 20 = 120, hoped this helped.
Answer:
42
Step-by-step explanation:
because 2+2+2=6×7=42
