Answer:
y = 3/4x +4
Step-by-step explanation:
From point A to point B, you show a rise of 3 units and a run of 4 units. (The rise is the difference in height of the first two squares; the run is the side length of the first square.) The ratio rise/run = 3/4 is the slope of the line you want.
The upper-left corner of the first square is the y-intercept of the line (4). So, in slope-intercept form, the equation of the dotted line is ...
y = mx + b . . . . . m = slope; b = y-intercept
y = 3/4x + 4
Answer: The area is 268 cm squared (approximately)
Step-by-step explanation: The area of a parallelogram is given as ;
Area = b x h
Where b is the base and h is the vertical height. However the vertical height is not given, so we shall apply the trigonometric ratio to determine the vertical height. If we draw a straight line from the the top right vertex down to the base, we would have constructed a right angled triangle with hypotenuse 13cm, and reference angle 79 degrees. We can now calculate the vertical height as follows;
Sin 79 = opposite/hypotenuse
Sin 79 = h/13
By cross multiplication we now have
Sin 79 x 13 = h
0.9816 x 13 = h
12.76 = h
With the vertical height now known, we can calculate the area as follows
Area = b x h
Area = 21 x 12.76
Area = 267.96 cm squared
Whats the question? I dont understand whats happenign here.
Answer:
D) ![\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%5Cfrac%7B5%7D%7B4%7D%5C%5C-%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For matrix ![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
the inverse matrix is the transpose of the cofactor matrix, divided by the determinant: ![\dfrac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bad-bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dd%26-b%5C%5C-c%26a%5Cend%7Barray%7D%5Cright%5D)
Your inverse matrix is: ![\dfrac{1}{2(-3)-(1)(2)}\left[\begin{array}{cc}-3&-1\\-2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%28-3%29-%281%29%282%29%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-1%5C%5C-2%262%5Cend%7Barray%7D%5Cright%5D)
so the solution is ...
![\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{cc}\frac{3}{8}&\frac{1}{8}\\\frac{1}{4}&-\frac{1}{4}\end{array}\right] \cdot\left[\begin{array}{c}2\\4\end{array}\right] =\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right] \qquad\text{matches selection D}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B8%7D%26%5Cfrac%7B1%7D%7B8%7D%5C%5C%5Cfrac%7B1%7D%7B4%7D%26-%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%5Cfrac%7B5%7D%7B4%7D%5C%5C-%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%5Ctext%7Bmatches%20selection%20D%7D)
Answer:
Left, Up
Step-by-step explanation:
Since -2 is to the left of 0 on the x-axis, we are moving left 2 units.
Since 7 is above 0 on the y-axis, we are moving up 7 units.
