Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
It has to obey all the polynomial rules, like 3x^4 or 6x, it has to have the base then the power.
Answer:
56766.97
Step-by-step explanation:
Answer:
Theta = 59 degrees
Step-by-step explanation:
Here, we want to get the value of the marked angle
To do this, we use the appropriate trigonometric ratio
From what we have,
The side 42 ft is adjacent the angle given
The side facing the right angle is 82 ft
The trigonometric ratio that connects the adjacent and the hypotenuse is cosine. It is the ratio of the adjacent to the hypotenuse
Cos theta = 42/82
theta = cos^-1 0.5122
theta= 59.189
To the nearest degrees, this is 59 degrees
I = Prt
t = I/(Pr)
.. = (5000 -4713.54)/(5000*0.125)
.. = 165/360
The time period of the note is 165 days.
