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Nina [5.8K]
2 years ago
6

The perimeter of a rectangular room is 52 feet. The length is 2 more than the width. What is the width of the room?

Mathematics
1 answer:
Otrada [13]2 years ago
7 0

Answer:

10

Step-by-step explanation:

i think its 10 maybe cuz if u see

the perimeter of a rectangular room is 52 feet. right?

then then height is 2 more than the width. what is the width of the room? so am I right copying the question? yes the question is right copied ok!

now see when u subtract 2 from 12 it gives u 10 and length i as 2 more than the width so maybe 10

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Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

<u><em>5*[∫x^{2}dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>

<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

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