Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
A and B are points on j.
C and D are points on k.
Join AD and BC.
ABCD is a quadrilateral.
Clearly, the quadrilateral ABCD is the only plane that contains the points A, B, C and D.
Hence, correct answer is option A. Exactly one.
Answer:
16+c
Step-by-step explanation:
Sum means we will have to add. When it says "sum of sixteen and c" it is telling us to add both sixteen and c together.
Answer:
x > - 1
Step-by-step explanation:
Given
- 3x - 5 < - 2 ( add 5 to both sides )
- 3x < 3
Divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity
x > - 1
