slope = (y2-y1)/(x2-x1)
= (2--1)/(5-1)
= (2+1)/(4)
=3/4
The point slope from of a line is
y-y1 = m(x-x1)
y--1 = 3/4 (x-1)
y+1 = 3/4 (x-1)
9514 1404 393
Answer:
x^2 -4x +2 = 0
Step-by-step explanation:
The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...
(x -2-√2)(x -2+√2) = 0
Expanding this, we get ...
(x -2)^2 -(√2)^2 = 0
x^2 -4x +4 -2 = 0
x^2 -4x +2 = 0 . . . . the equation you're looking for
Answer:
-20/3 & -40/3
Step-by-step explanation:
Let’s say that the 1st number is X and the 2nd number is Y.
Given that x:y = 1:2 => x/y = 1/2 => 2x = y
and a-5/y+4 = 5/4 (The first number is decreased by 5 and the second number is increased by 4.)
=> 4(x - 5) = 5 (y + 4)
=> 4x - 20 = 5y + 20
=> 4x - 5y = 40
As, 2x = y , 4x = 2y
=> 2y - 5y = 40
=> -3y = 40
=> y = -40/3 ; x = y/2 = -20/3
This might be confusing but I hope this helps :)
