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joja [24]
3 years ago
13

What value of x is in the solution set of 3(x – 4) ≥ 5x + 2?

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0
Hey!


To start solving equation, we should first distribute the parenthesis. We do this so that we can get rid of the parenthesis.

<em>Original Equation :</em>
3 ( x - 4 ) ≥ 5x + 2

<em>New Equation {Changed by Distribution} :</em>
3x - 12 ≥ 5x + 2

Next, we'd add 12 to both sides of the equation to get rid of the 12 on the left side of the equation.

<em>Old Equation :</em>
3x - 12 ≥ 5x + 2

<em>New Equation {Changed by Adding 12 to Both Sides} :</em>
3x ≥ 5x + 14

Now we subtract 5x from both sides of the equation to get rid of the 5x from the right side.

<em>Old Equation :</em>
3x ≥ 5x + 14

<em>New Equation {Changed by Subtracting 5x From Both Sides} :</em>
-2x ≥ 14

Now we must inverse the inequality. To do that we multiply both sides by -1.

<em>Old Equation :</em>
-2x ≥ 14

<em>New Equation {Changed by Inverse} :</em>
2x ≤ -14

Just by looking at the equation, you can easily tell that it needs to be simplified. So, that's what we'll do next.

<em>Old Equation :</em>
2x ≤ -14

<em>New Equation {Changed by Dividing Both Sides by Two} :</em>
x ≤ -7

Seeing as the equation cannot be simplified any further, we have our answer.
<em>The value of x in the inequality </em><span><em>of 3 ( x – 4 ) ≥ 5x + 2, is </em> x </span>≤ -7.

Hope this helps!


- Lindsey Frazier ♥
belka [17]3 years ago
5 0

Answer:

x \leq -7

(-∞, -7)

Step-by-step explanation:

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If p varies directly as q and q= 70 when p= 10, find q when p = 12
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\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] ~\dotfill

\stackrel{\textit{"p" varies directly as "q"}}{p~~ = ~~kq}\qquad \textit{we also know that} \begin{cases} q=70\\ p=10 \end{cases}\implies 10=k70 \\\\\\ \cfrac{10}{70}=k\implies \cfrac{1}{7}=k\hspace{15em}\boxed{p=\cfrac{1}{7}k} \\\\\\ \textit{when p = 12, what is "q"?}\qquad 12=\cfrac{1}{7}q\implies 12=\cfrac{q}{7}\implies 84=q

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Step-by-step explanation:

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Step-by-step explanation:

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