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klasskru [66]
3 years ago
7

What is the formula for a pyramid in surface area ?

Mathematics
2 answers:
weqwewe [10]3 years ago
7 0
[Base Area] + 1/2 × Perimeter × [Slant Length] is when the sides are the same.
But...when they are different: [Base Area] + [Lateral Area]
Hope this helps!
Rufina [12.5K]3 years ago
3 0
All surface area formulas are the same so just mutiply the base 2 and figure it out hope this helps
You might be interested in
Three numbers have absolute values of 2,4 and 9. The product of all the numbers is positive.
Margaret [11]
The absolute value of a number is how far away it is from 0 on a number line.
Example) 2 is two numbers away from 0, but neg. 2 (-2) is also two numbers away from 0

So basically. A positive number has the absolute value of itself. (2= a value of 2) and negative numbers have the absolute value of the positive form of that number. (-9= a value of 9)

Numbers that have the absolute value of 2: 2 and -2
Numbers that have the absolute value of 4: 4 and -4
Numbers that have the absolute value of 9: 9 and -9

You are looking to add your numbers together to make a positive.

So the answer is the positive answers to the absolute values: 2,4,9

2+4+9=15

15 is a positive number.
8 0
3 years ago
True or false? in order to inscribe a circle in a triangle, the circle's center must be placed at the incenter of the triangle.
guajiro [1.7K]

Answer:

The given statement is true.

Step-by-step explanation:

In order to inscribe a circle in a triangle, the circle's center must be placed at the incenter of the triangle.

This statement is true.

The INCENTER is the center of the circle that is inscribed in the triangle. Like the centroid, the incenter is always inside the triangle.

6 0
4 years ago
5x+7y=3914. I'm not quite sure how to write the x and y! First answer will get Brainliest, thanks!
Stolb23 [73]

Answer:

hanges made to your input should not affect the solution:

(1): Dot was discarded near "4.".

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    5*x+7*y-(3914)=0

STEP

1

:

Equation of a Straight Line

1.1     Solve   5x+7y-3914  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  5x+7y-3914  = 0 and calculate its properties

Graph of a Straight Line :

 

Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 3914/7 so this line "cuts" the y axis at y=559.14286

 y-intercept = 3914/7  = 559.14286

Calculate the X-Intercept :

When y = 0 the value of x is 3914/5 Our line therefore "cuts" the x axis at x=782.80000

 x-intercept = 3914/5  = 782.80000

Calculate the Slope :

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 559.143 and for x=2.000, the value of y is 557.714. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 557.714 - 559.143 = -1.429 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

   Slope     = -1.429/2.000 = -0.714

Geometric figure: Straight Line

 Slope = -1.429/2.000 = -0.714

 x-intercept = 3914/5 = 782.80000

 y-intercept = 3914/7 = 559.14286

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Rationalise:<br>(1)              4/(2+root3+root7)<br>(2)              4/(2root3+root5)
Temka [501]
\frac{4}{2+\sqrt3+\sqrt7}\cdot\frac{2-(\sqrt3+\sqrt7)}{2-(\sqrt3+\sqrt7)}=\frac{8-4\sqrt3-4\sqrt7}{2^2-(\sqrt3+\sqrt7)^2}=\frac{8-4\sqrt3-4\sqrt7}{4-3-2\sqrt{3\cdot7}-7}\\\\=\frac{8-4\sqrt3-4\sqrt7}{-6-2\sqrt{21}}=\frac{-2(2\sqrt3+2\sqrt7-4)}{-2(3+\sqrt{21})}=\frac{2\sqrt3+2\sqrt7-4}{3+\sqrt{21}}\cdot\frac{3-\sqrt{21}}{3-\sqrt{21}}\\\\=\frac{6\sqrt3-2\sqrt{63}+6\sqrt7-2\sqrt{147}-12+4\sqrt{21}}{3^2-(\sqrt{21})^2}=\frac{6\sqrt3-2\sqrt{9\cdot7}+6\sqrt7-2\sqrt{49\cdot3}-12+4\sqrt{21}}{9-21}

=\frac{6\sqrt3-6\sqrt7+6\sqrt7-14\sqrt3-12+4\sqrt{21}}{-12}=\frac{-8\sqrt3+4\sqrt{21}-12}{-12}=\frac{-4(2\sqrt3-\sqrt{21}+3)}{-12}\\\\=\frac{2\sqrt3-\sqrt{21}+3}{3}

==============================================================

\frac{4}{2\sqrt3+\sqrt5}\cdot\frac{2\sqrt3-\sqrt5}{2\sqrt3-\sqrt5}=\frac{8\sqrt3-4\sqrt5}{(2\sqrt3)^2-(\sqrt5)^2}=\frac{8\sqrt3-4\sqrt5}{4\cdot3-5}=\frac{8\sqrt3-4\sqrt5}{12-5}\\\\=\frac{8\sqrt3-4\sqrt5}{7}
4 0
4 years ago
Read 2 more answers
Given that PS is the perpendicular bisector of QR, PQ=3.5m+18, and PR=6m+3, identify PQ.
kolbaska11 [484]

Answer:

PQ=39\ units

Step-by-step explanation:

we know that

QS=RS ----> equation A

Applying Pythagoras Theorem

PQ^2=SP^2+QS^2 -----> equation B

PR^2=SP^2+RS^2-----> equation C

substitute equation A in equation C

PR^2=SP^2+QS^2

we have that

PR^2=PQ^2

so

PR=PQ

substitute the given values

6m+3=3.5m+18

Solve for m

6m-3.5m=18-3

2.5m=15

m=6

Find the value of PQ

PQ=3.5m+18

substitute the value of m

PQ=3.5(6)+18

PQ=39\ units

8 0
4 years ago
Read 2 more answers
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