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3 years ago

Which property justifies the following equation?

Mathematics

1 answer:

Leviafan [203]3 years ago

5 0

1. . D . Identity , when you odd both properties it will always to be true on both sides

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Problem #18

Arisa [49]

Answer:

Step-by-step explanation:

Step one:

given data

dimension of the box

lengh= 5 in

width= 2 in

height =4 in

Required

the volume of the box

the expression for the volume is

V=L*W*H

V=5*2*4

V=40 in^3

Hence the volume of sand the box can take is 40in^3

6 0

2 years ago

Here are scores for two softball teams for seven innings. Each team's total score is the sum of the numbers in its row. Rosie's

gladu [14]

Answer:

<h2> T<u>he Susans Bees lost by </u><u>3</u><u> points.</u></h2>

Step-by-step explanation:

Rosie's Riveters has 13 points in all.

The Susans Bees have 10 points in all.

13 - 10 = 3.

5 0

2 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

What is the answer for -0.04 times -0.1?

Orlov [11]

<span><span>The answer is 0.004. You are aware you could have just used a calculator or used google (Since you're posting on here you have access to the internet)</span><span>
</span></span>

5 0

2 years ago

Read 2 more answers

35,000 divided by 120

Naya [18.7K]

Answer:

291.666666667

Step-by-step explanation:

Rounds to 291.7

8 0

2 years ago

Read 2 more answers